For z = (x + y)-2, and x = u2+v2 and y=uv, find the partial derivatives at u = v =1

Question

For z = (x + y)^-2, and x = u²+v² and y=uv, find the partial derivatives<img src="data:image/png;base64, iVBORw0KGgoAAAANSUhEUgAAAEgAAAAwCAIAAAA9/qu8AAAABGdBTUEAALGPC/xhBQAAAAlwSFlzAAAOwwAADsMBx2+oZAAABRdJREFUaEPtmH1ME2c

Answer 1

<img src="data:image/png;base64, iVBORw0KGgoAAAANSUhEUgAAAQwAAACxCAIAAAC+zRTbAAAABGdBTUEAALGPC/xhBQAAAAlwSFlzAAAOwwAADsMBx2+oZAAAGPlJREFUeF7t3QlYE2f+B/Du/3m2+992t+22u926/nttux54i7csKtb7ADyAikKRCloVDxAQ8T4REeRUFAXkUm6hHtwKKAJFLHIoIIciEDkFJHky8/CfSQIkYSb