Question

∫ -x ln(yx) dx = ?

Answer 1

Integration by parts : A = ∫ u dv = uv - ∫ v du = uv – B ;

u = ln(yx) ; du = (1/x) dx ;

dv = -x dx ; v = (-1/2) x² ;

uv = ln(yx) (-1/2) x^2</s